Hello Aspirants,
Welcome to Online Quants Test in AffairsCloud.com. We are starting SBI PO 2017 Practice Course and we are creating sample questions in Quant section, type of which will be asked in SBI PO 2017 !!!
 Click Here to View Cumulus: SBI PO 2017 Course
 SBI PO Practice 2017: Reasoning Test
 SBI PO Practice 2017: Quants Test
 SBI PO Practice 2017: English Test
Help: Share Our SBI PO 2017 Course page to your Friends & FB Groups
_____________________________________________________________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirection: Q (15) Below is the performance of two candidates Rohan and Radha in various subjects. Study the following chart and answer the questions
What is the ratio of total marks scored by Radha to total marks secured by Rohan in all the subjects ?
Correct
Explanation:
250/225=10/9
10:9Incorrect
Explanation:
250/225=10/9
10:9 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirection: Q (15) Below is the performance of two candidates Rohan and Radha in various subjects. Study the following chart and answer the questions
Had Rohan scored 50 % more marks than he has scored in Quants, then the marks scored by Rohan in Quants would have been how much percentage more than that of marks scored by Radha in General Awareness?
Correct
Explanation:
New marks of Rohan=90
Percentage=9080/80*100=12.5%Incorrect
Explanation:
New marks of Rohan=90
Percentage=9080/80*100=12.5% 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirection: Q (15) Below is the performance of two candidates Rohan and Radha in various subjects. Study the following chart and answer the questions
If during rechecking it was found that the marks of Radha and Rohan were interchanged in English by mistake, hence the ratio of total marks scored by Rohan to Radha after correction
Correct
Explanation:
New marks of Rohan250 Previous marks of Rohan225
New marks of Radha225 Previous marks of Rohan250
New Ratio10/9 Previous Ratio9/10Incorrect
Explanation:
New marks of Rohan250 Previous marks of Rohan225
New marks of Radha225 Previous marks of Rohan250
New Ratio10/9 Previous Ratio9/10 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirection: Q (15) Below is the performance of two candidates Rohan and Radha in various subjects. Study the following chart and answer the questions
If suppose a new subject Computer is introduced, Radha scores 50 marks out of 100 in computer, how much percent more marks than the marks scored by Radha in computer should Rohan score so that their overall marks becomes same.
Correct
Explanation:
Total marks of radha in all 5 subject300
Marks of rohan in 4 subjects (except computer)225
Therefore marks required by Rohan300225=75
Percentage=7550/50*100Incorrect
Explanation:
Total marks of radha in all 5 subject300
Marks of rohan in 4 subjects (except computer)225
Therefore marks required by Rohan300225=75
Percentage=7550/50*100 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirection: Q (15) Below is the performance of two candidates Rohan and Radha in various subjects. Study the following chart and answer the questions
What is the overall percentage of Radha in all 4 subjects(Max marks in all subject 100) ?
Correct
Explanation:
Overall percentage250/400*100=62.5%Incorrect
Explanation:
Overall percentage250/400*100=62.5% 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeTwo liquids A and B are in ratio 4:1 in container X and 3:5 in container Y. In what ratio should the content of both container be mixed so that the resulting mixture has A and B in ratio 2:3?
Correct
Explanation:
Let the ratios in which they are mixed is x and y
Therefore A=4/5x+3/8y
B=1/5x+5/8y
Now A/B=2/3
On solving we get x:y=1:16Incorrect
Explanation:
Let the ratios in which they are mixed is x and y
Therefore A=4/5x+3/8y
B=1/5x+5/8y
Now A/B=2/3
On solving we get x:y=1:16 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude8 women can complete the work in 10 days and 5 men can complete the work in 8 days where as 25 children can complete in 4 days. 16 women,4 men and 20 children work together for 2 days.If only women were to complete the remaining work in 1 day,how many women would be required?
Correct
Explanation:
(M1)(H1)(D1)/(W1)=(M2)(H2)(D2)/(W2)
Hence (8*10)W=(5*8)M=(25*4)C
4W=2M=5C
Now 16W+4M+20C=16W+8W+16W=40W
8W one day work=1/10
40W one day work=(1/10)*(40/8)=1/2
40W 2 day work=1
Remaining Work=0
Work is already completed.Incorrect
Explanation:
(M1)(H1)(D1)/(W1)=(M2)(H2)(D2)/(W2)
Hence (8*10)W=(5*8)M=(25*4)C
4W=2M=5C
Now 16W+4M+20C=16W+8W+16W=40W
8W one day work=1/10
40W one day work=(1/10)*(40/8)=1/2
40W 2 day work=1
Remaining Work=0
Work is already completed. 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA tank has a leak which would empty it in 6 hrs. A tap pumps water @ 8 litres/ minute into the tank, and it is now emptied in 12 hrs. What is the capacity of tank?
Correct
Explanation:
In the absence of leak time taken by tap to fill tank=12*6/126=12hour
Water filled in 1 hour=8*60=480L
Therefore water filled in 12 hour=12*480=5760LIncorrect
Explanation:
In the absence of leak time taken by tap to fill tank=12*6/126=12hour
Water filled in 1 hour=8*60=480L
Therefore water filled in 12 hour=12*480=5760L 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA man borrows Rs. 25,000 at 20% compound interest. At the end of every year he pays Rs. 5000 as part of repayment. How much does he still owe after three such installments?
Correct
Explanation:
C.I of 20000 in 3 years =25000*(1+20/100)^3=43200Rs
But as we are paying 2000Rs at the end of every year hence that should should be subtracted at the end of every year and the CI on remaining amount must be calculated.
Therefore CI of 2000Rs that is paid at the end of 1^{st} year=5000*(1+10/100)^2=7200
CI of 2000Rs that is paid at the end of 2nd year=5000*(1+10/100)^1=6000
Hence due amount after 3^{rd} payment=43200(7200+6000+5000)=25000Incorrect
Explanation:
C.I of 20000 in 3 years =25000*(1+20/100)^3=43200Rs
But as we are paying 2000Rs at the end of every year hence that should should be subtracted at the end of every year and the CI on remaining amount must be calculated.
Therefore CI of 2000Rs that is paid at the end of 1^{st} year=5000*(1+10/100)^2=7200
CI of 2000Rs that is paid at the end of 2nd year=5000*(1+10/100)^1=6000
Hence due amount after 3^{rd} payment=43200(7200+6000+5000)=25000 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIn a triangle, two sides of right angle triangle are 8 cm and 6 cm. If the triangle is revolved along the 8 cm side, the curved surface area of the cone so formed will be
Correct
Explanation:
Radius of cone =8cm
Slant height=10cm
Curved surface area=πrl=22/7*6*10=188.4 cubic cmIncorrect
Explanation:
Radius of cone =8cm
Slant height=10cm
Curved surface area=πrl=22/7*6*10=188.4 cubic cm
_____________________________________________________________________
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 Share your Marks in Comment Sections